*Part A. A 160.0-g sample of a certain bronze is 90.0% copper by mass and 10.0% tin. Which metal can be called the solvent, and which the solute?*

**copper is the solvent **and **tin is the solute.**

**Part B:**

$\overline{)\mathbf{molarity}\mathbf{}\mathbf{\text{(M)}}\mathbf{=}\frac{\mathbf{mol}}{\mathbf{L}}}$

**tin → solute**

**Calcualte moles tin:**

$\mathbf{mass}\mathbf{}\mathbf{tin}\mathbf{=}\frac{\mathbf{10}\mathbf{\%}}{\mathbf{100}}\mathbf{\times}\mathbf{160}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{g}$

**mass tin = 16.0 g**

molar mass tin = 118.71 g/mol

$\mathbf{moles}\mathbf{}\mathbf{tin}\mathbf{=}\mathbf{16}\mathbf{.}\mathbf{0}\mathbf{}\overline{)\mathbf{g}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mol}}{\mathbf{118}\mathbf{.}\mathbf{71}\mathbf{}\overline{)\mathbf{g}}}$

**moles tin = 0.1347 mol**

**Calculate the volume of solution in L:**

Bronze is a *solid solution* of Cu(s) and Sn(s); solutions of metals like this that are solids are called *alloys*. There is a range
of compositions over which the solution is considered a
bronze. Bronzes are stronger and harder than either copper or
tin alone.

Part A. A 160.0-g sample of a certain bronze is 90.0% copper by mass and 10.0% tin. Which metal can be called the solvent, and which the solute?

**Part B. Based on Part A, calculate
the concentration of the solute metal in the alloy in units of
molarity, assuming a density of 7.9 g/cm ^{3}.**

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