Problem: Procedure for titrating an acid against a standard solution of NaOH. The acid-base indicator, phenolphthalein, is colorless in acidic solution but takes on a pink color in basic solution. How would the volume of standard solution added change if that solution were Ba(OH)2(aq) instead of NaOH(aq)?

FREE Expert Solution

The dissociation of NaOH is:

NaOH → Na+ + OH

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Problem Details


1) 20.0 milliliters of acid solution added to flask. 2) A few drops of acid-base indicator added to flask. 3) Standard NaOH solution added to flask from burette, on which the initial volume reading of the base can be taken. 4) Solution becomes basic on passing equivalence point, triggering indicator color change. The solution in the flask has turned a bright pink color, and the final volume reading is taken from the burette.


Procedure for titrating an acid against a standard solution of NaOH. The acid-base indicator, phenolphthalein, is colorless in acidic solution but takes on a pink color in basic solution. How would the volume of standard solution added change if that solution were Ba(OH)2(aq) instead of NaOH(aq)?

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