ZnCO3(s) → ZnO(s) + CO2(g)
Recall that at constant pressure, heat is equivalent to enthalpy.
The decomposition of ZnCO3(s) into ZnO(s) and CO2(g) at constant pressure requires the addition of 71.5 kJ of heat per mole of ZnCO3.
What is the enthalpy of the reaction above?
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