Problem: The decomposition of ZnCO3(s) into ZnO(s) and CO2(g) at constant pressure requires the addition of 71.5 kJ of heat per mole of ZnCO3.What is the enthalpy of the reaction above?

FREE Expert Solution

Balanced reaction:

ZnCO3(s) → ZnO(s) + CO2(g) 


Recall that at constant pressure, heat is equivalent to enthalpy.

View Complete Written Solution
Problem Details

The decomposition of ZnCO3(s) into ZnO(s) and CO2(g) at constant pressure requires the addition of 71.5 kJ of heat per mole of ZnCO3.

What is the enthalpy of the reaction above?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Thermochemical Equation concept. You can view video lessons to learn Thermochemical Equation. Or if you need more Thermochemical Equation practice, you can also practice Thermochemical Equation practice problems.