Ch.6 - Thermochemistry WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A 100.0-g bar of gold is heated from 25 oC to 50 oC, during which it absorbs 322 J of heat. Assume the volume of the gold bar remains constant.Based on the data, calculate the specific heat of Au (s).

Solution: A 100.0-g bar of gold is heated from 25 oC to 50 oC, during which it absorbs 322 J of heat. Assume the volume of the gold bar remains constant.Based on the data, calculate the specific heat of Au (s).

Problem

A 100.0-g bar of gold is heated from 25 oC to 50 oC, during which it absorbs 322 J of heat. Assume the volume of the gold bar remains constant.

Based on the data, calculate the specific heat of Au (s).

Solution

Specific heat of a substance is given by:


<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>c</mi><mo>&#xA0;</mo><mo>=</mo><mfrac><mrow><mo>&#xA0;</mo><mi>q</mi></mrow><mrow><mi>m</mi><mo>.</mo><mo>&#x2206;</mo><mi>T</mi></mrow></mfrac></math>


We are given the values of m, q and the initial and final temperatures.

Note that

<math xmlns="http://www.w3.org/1998/Math/MathML"><mstyle mathsize="20px"><mrow><mo>&#x2206;</mo><mi mathvariant="normal">T</mi><mo>&#xA0;</mo><mo>=</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">T</mi><mi>final</mi></msub><mo>&#xA0;</mo><mo>-</mo><mo>&#xA0;</mo><msub><mi mathvariant="normal">T</mi><mi>initial</mi></msub></mrow></mstyle></math>


Also, because heat is being absorbed, the value of q will be positive.


We can plug in these values into this equation.


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