We are asked to calculate ΔH for the formation of 1.36 mol of O2.
2 KClO3(s) → 2 KCl(s) + 3 O2(g), ΔH = –89.4kJ
At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KClO3: 2 KClO3(s) → 2 KCl(s) + 3 O2(g), ΔH = –89.4kJ
For this reaction, calculate ΔH for the formation of 1.36 mol of O2.
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