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Problem: The methane molecule, CH4, has the geometry shown in following figure. Imagine a hypothetical process in which the methane molecule is "expanded," by simultaneously extending all four C–H bonds to infinity. We then have the process CH4(g) → C(g) + 4 H(g)Suppose that 3.70 g CH4(g) is reacted with 1.13 g F2(g), forming CF4(g) and HF(g) as sole products. What is the limiting reagent in this reaction?

FREE Expert Solution

We are asked what is the limiting reagent in this reaction.


Balanced reaction: 

CH4(g) +  4 F2(g) → CF4(g) + 4 HF(g)


Calculate product using both reactants: 


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Problem Details
The methane molecule, CH4, has the geometry shown in following figure. Imagine a hypothetical process in which the methane molecule is "expanded," by simultaneously extending all four C–H bonds to infinity. We then have the process CH4(g) → C(g) + 4 H(g)
The figure shows a ball-and-stick model and a perspective drawing of CH4.

Suppose that 3.70 g CH4(g) is reacted with 1.13 g F2(g), forming CF4(g) and HF(g) as sole products. What is the limiting reagent in this reaction?

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