Recall that at constant pressure, ** heat is equivalent to enthalpy**.

$\overline{){\mathbf{q}}\mathbf{\left(}\mathbf{heat}\mathbf{\right)}{\mathbf{=}}{\mathbf{\u2206}}{\mathbf{H}}\mathbf{\left(}\mathbf{enthalpy}\mathbf{\right)}}$

You may want to reference (Pages 191 - 192) Section 5.8 while completing this problem.

The sun supplies about 1.1 kilowatt(s) of energy for each square meter of surface area (1.1
kW/m^{2}, where a watt = 1 J/s). Plants produce the equivalent of about 0.21
g of sucrose (C_{12}H_{22}O_{11}) per hour per square meter.

Assuming that the sucrose is produced as follows, calculate the percentage of sunlight used to produce sucrose.

12 CO_{2}(g) + 11 H_{2}O(l) → C_{12}H_{22}O_{11} + 12O_{2}(g), ΔH = 5645kJ

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