# Problem: You may want to reference (Pages 191 - 192) Section 5.8 while completing this problem.The sun supplies about 1.1 kilowatt(s) of energy for each square meter of surface area (1.1 kW/m2, where a watt = 1 J/s). Plants produce the equivalent of about 0.21 g of sucrose (C12H22O11) per hour per square meter.Assuming that the sucrose is produced as follows, calculate the percentage of sunlight used to produce sucrose.12 CO2(g) + 11 H2O(l) → C12H22O11 + 12O2(g), ΔH = 5645kJ

###### FREE Expert Solution

Recall that at constant pressure, heat is equivalent to enthalpy.

$\overline{){\mathbf{q}}\mathbf{\left(}\mathbf{heat}\mathbf{\right)}{\mathbf{=}}{\mathbf{∆}}{\mathbf{H}}\mathbf{\left(}\mathbf{enthalpy}\mathbf{\right)}}$

94% (180 ratings)
###### Problem Details

You may want to reference (Pages 191 - 192) Section 5.8 while completing this problem.

The sun supplies about 1.1 kilowatt(s) of energy for each square meter of surface area (1.1 kW/m2, where a watt = 1 J/s). Plants produce the equivalent of about 0.21 g of sucrose (C12H22O11) per hour per square meter.

Assuming that the sucrose is produced as follows, calculate the percentage of sunlight used to produce sucrose.

12 CO2(g) + 11 H2O(l) → C12H22O11 + 12O2(g), ΔH = 5645kJ

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Nature of Energy concept. You can view video lessons to learn Nature of Energy. Or if you need more Nature of Energy practice, you can also practice Nature of Energy practice problems.