# Problem: You may want to reference (Pages 191 - 192) Section 5.8 while completing this problem.The sun supplies about 1.1 kilowatt(s) of energy for each square meter of surface area (1.1 kW/m2, where a watt = 1 J/s). Plants produce the equivalent of about 0.21 g of sucrose (C12H22O11) per hour per square meter.Assuming that the sucrose is produced as follows, calculate the percentage of sunlight used to produce sucrose.12 CO2(g) + 11 H2O(l) → C12H22O11 + 12O2(g), ΔH = 5645kJ

###### FREE Expert Solution

Recall that at constant pressure, heat is equivalent to enthalpy.

$\overline{){\mathbf{q}}\mathbf{\left(}\mathbf{heat}\mathbf{\right)}{\mathbf{=}}{\mathbf{∆}}{\mathbf{H}}\mathbf{\left(}\mathbf{enthalpy}\mathbf{\right)}}$

###### Problem Details

You may want to reference (Pages 191 - 192) Section 5.8 while completing this problem.

The sun supplies about 1.1 kilowatt(s) of energy for each square meter of surface area (1.1 kW/m2, where a watt = 1 J/s). Plants produce the equivalent of about 0.21 g of sucrose (C12H22O11) per hour per square meter.

Assuming that the sucrose is produced as follows, calculate the percentage of sunlight used to produce sucrose.

12 CO2(g) + 11 H2O(l) → C12H22O11 + 12O2(g), ΔH = 5645kJ