Reaction: 4 NH3(l) + 3 O2(g) → 2 N2(g) + 6 H2O(g)
Ammonia (NH3) boils at -33oC; at this temperature it has a density of 0.81 g/cm3. The enthalpy of formation of NH3(g) is -46.2 kJ/mol, and the enthalpy of vaporization of NH3(l) is 23.2 kJ/mol.
Calculate the enthalpy change when 4 L of liquid NH3 is burned in air to give N2(g) and H2O(g).
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