Step 1

**$\mathbf{1050}\mathbf{}\frac{\mathbf{m}}{\mathbf{h}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{h}}{\mathbf{3600}\mathbf{}\mathbf{s}}$ = 0.2917 m/s**

At 20 ^{o}C (approximately room temperature) the average velocity of N_{2} molecules in air is 1050 mph.

What is the total kinetic energy of 1 mol of N_{2} molecules moving at this speed?

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