We are asked to balance the forward reaction with whole-number coefficients.
CH3OH(l) + 3/2 O2(g) → CO2(g) + 2 H2O(l)
The reaction is already balanced, we only need to make the coefficient whole numbers.
Consider the combustion of liquid methanol, CH3OH(l): CH3OH(l) + 3/2 O2(g) → CO2(g) + 2 H2O(l), ΔH = –726.5 kJ
Balance the forward reaction with whole-number coefficients.
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