exothermic → more thermodynamically favorable
endothermic → less thermodynamically favorable
Consider the combustion of liquid methanol, CH3 OH(l): CH3OH(l) + 3/2 O2(g) → CO2(g) + 2 H2O(l), ΔH = –726.5kJ
Which is more likely to be thermodynamically favored, the forward reaction or the reverse reaction?
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