Given: CH3OH(l) + 3/2 O2 (g) → CO2(g) + 2 H2O(l), ΔH = –726.5 kJ
Balancing the forward reaction with whole-number coefficients:
[ CH3OH(l) + 3/2 O2 (g) → CO2(g) + 2 H2O(l) ] x 2
2 CH3OH(l) + 3 O2 (g) → 2 CO2(g) + 4 H2O(l)
Consider the combustion of liquid methanol, CH3OH(l): CH3OH(l) + 3/2 O2 (g) → CO2(g) + 2 H2O(l), ΔH = –726.5kJ
Balance the forward reaction with whole-number coefficients. What is ΔH for the reaction represented by this equation?
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