Problem: Consider the combustion of liquid methanol, CH3OH(l): CH3OH(l) + 3/2 O2 (g) → CO2(g) + 2 H2O(l), ΔH = –726.5kJWhat is the enthalpy change for the reverse reaction?

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forward reaction: ΔH = –726.5kJ


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Consider the combustion of liquid methanol, CH3OH(l)CH3OH(l) + 3/2 O2 (g) → CO2(g) + 2 H2O(l), ΔH = –726.5kJ

What is the enthalpy change for the reverse reaction?

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