We are being asked to calculate the concentration (molarity) of the acid if 23.9 mL of strontium hydroxide solution was needed to neutralize a 31.5 mL aliquot of nitric acid solution.
Strontium hydroxide, Sr(OH)2, is a strong base. Nitric acid, HNO3, is a strong acid.
So, the titration of nitric acid solution with strontium hydroxide solution is a strong acid strong base titration.
The chemical equation of the reaction is
Sr(OH)2(aq) + HNO3(aq) → Sr(NO3)2(aq) + H2O(l)
During titration, Sr(OH)2 reacts with 2 HNO3.
The amount of HNO3 in the solution can be determined by the total amount of Sr(OH)2 used.
We’re going to calculate for the concentration of HNO3, using the following steps:
1. Calculate moles of Sr(OH)2
2. Determine moles of HNO3
3. Calculate the concentration of HNO3
If 23.9 mL of the strontium hydroxide solution (1.47 M) was needed to neutralize a 31.5 mL aliquot of the nitric acid solution, what is the concentration (molarity) of the acid?
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