🤓 Based on our data, we think this question is relevant for Professor Cook's class at LSU.

$\overline{){\mathbf{Molarity}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liters}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}\phantom{\rule{0ex}{0ex}}\mathbf{\left[}\mathbf{Sr}{\left(\mathrm{OH}\right)}_{\mathbf{2}}\mathbf{\right]}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{moles}\mathbf{}\mathbf{Sr}{\left(\mathrm{OH}\right)}_{\mathbf{2}}}{\mathbf{Liters}\mathbf{}\mathbf{water}}\phantom{\rule{0ex}{0ex}}\mathbf{\left[}\mathbf{Sr}{\left(\mathrm{OH}\right)}_{\mathbf{2}}\mathbf{\right]}\mathbf{}\mathbf{=}\frac{\mathbf{12}\mathbf{.}\mathbf{50}\mathbf{}\overline{)\mathbf{g}}\mathbf{}\mathbf{\times}{\displaystyle \frac{\mathbf{1}\mathbf{}\mathbf{mol}}{\mathbf{121}\mathbf{.}\mathbf{63}\mathbf{}\overline{)\mathbf{g}}}}}{\mathbf{50}\mathbf{.}\mathbf{00}\mathbf{}\overline{)\mathbf{mL}}\mathbf{}\mathbf{\times}{\displaystyle \frac{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\mathbf{L}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}}}$

(a) A strontium hydroxide solution is prepared by dissolving 12.50 g of Sr(OH)_{2} in water to make 50.00 mL of solution. What is the molarity of this solution?

**Next the strontium hydroxide solution prepared in part (a) is used to titrate a nitric acid solution of unknown concentration. Write a balanced chemical equation to represent the reaction between strontium hydroxide and nitric acid solutions.**