Problem: By titration, 15.0 mL of 0.1008 M sodium hydroxide is needed to neutralize a 0.2053-g sample of an organic acid. What is the molar mass of the acid if it is monopro-tic?

FREE Expert Solution

Once an acid is neutralized by a base it reaches the equivalence point, where:


moles acid=moles base


Also, recall that:

  • moles = molarity × volume
  • moles = mass/molar mass


This means:


molesacid=MVbase


  • Monoprotic acid (HA) → donates only 1 H+
    • 1 mole acid reacts with 1 mole NaOH
    • HA + NaOH → NaA + H2O


Solving for MMacid:


0.2053 gMMacid=0.1008 molNaOH L15.00  mL×10-3L1 mL


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Problem Details

By titration, 15.0 mL of 0.1008 M sodium hydroxide is needed to neutralize a 0.2053-g sample of an organic acid. What is the molar mass of the acid if it is monopro-tic?

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What scientific concept do you need to know in order to solve this problem?

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