We’re asked to **c****alculate the amount of HCN that gives the lethal dose** in a** small laboratory room measuring 13 ft x 16 ****ft x 8.0 ft **and given the** lethal dose of HCN** and **density of air**.

Recall that ** density** is the ratio of the mass and volume of an object:

$\overline{){\mathbf{density}}{\mathbf{=}}\frac{\mathbf{mass}}{\mathbf{volume}}}$

Also, the ** volume **is given by:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{l}}{\mathbf{\times}}{\mathbf{w}}{\mathbf{\times}}{\mathbf{h}}}$

where:

l = length, w = width, h = height

**To solve for the amount of HCN (in mg), we need to do these steps:**

*Step 1: Calculate the **volume of the small laboratory room*

*Step 2: Get the mass of air (inside the room) from its density and volume (from step 1) *

*Step 3: Solve for the lethal amount of HCN in the air inside the room based on its lethal dose*

Hydrogen cyanide, HCN, is a poisonous gas. The lethal dose is approximately 310 mg HCN per kilogram of air when inhaled.

Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 13 ft 16 ft 8.0 ft.

The density of air at 26°C is 0.00118 g/cm^{3}.

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