Determine the mass of octane used:

$\mathbf{mass}\mathbf{}{\mathbf{C}}_{\mathbf{8}}{\mathbf{H}}_{\mathbf{18}}\mathbf{=}\mathbf{6}\mathbf{}\overline{)\mathbf{mi}}\mathbf{\left(}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{gal}}}{\mathbf{21}\mathbf{.}\mathbf{5}\mathbf{}\overline{)\mathbf{mi}}}\mathbf{\right)}\mathbf{\left(}\frac{\mathbf{3}\mathbf{.}\mathbf{78541}\mathbf{}\overline{)\mathbf{L}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{gal}}}\mathbf{\right)}\mathbf{\left(}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{L}}}\mathbf{\right)}\mathbf{\left(}\frac{\mathbf{0}\mathbf{.}\mathbf{69}\mathbf{}\mathbf{g}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}\mathbf{\right)}\mathbf{=}$**728.911507 g C _{8}H**

Repeat the calculation for a truck that has a gas mileage of 6 mi/gal.

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