We’re asked to determine how many atoms are present in a cube of silver metal that measures 1.050 cm on each edge given its density.
We can calculate the # of Ag (silver) atoms using the following steps:
Step 1: Determine the volume of the silver cube. Recall that the volume of a cube is given by the equation:
l = length of edge of a cube
Step 2: Determine the mass of the silver cube from the given density from the equation:
This means that: Mass = density x volume
Step 3: Determine atoms Ag. The flow of the solution will be like this:
mass Ag (molar mass Ag) → moles Ag (Avogadro’s number) → atoms Ag
You are given a cube of silver metal that measures 1.050 cm on each edge. The density of silver is 10.5 g/cm3.
How many atoms are in this cube?