Problem: You are given a cube of silver metal that measures 1.050 cm on each edge. The density of silver is 10.5 g/cm3.How many atoms are in this cube?

FREE Expert Solution

We’re asked to determine how many atoms are present in a cube of silver metal that measures 1.050 cm on each edge given its density.


We can calculate the # of Ag (silver) atoms using the following steps:

Step 1: Determine the volume of the silver cube. Recall that the volume of a cube is given by the equation:


Volume=l3

l = length of edge of a cube


Step 2: Determine the mass of the silver cube from the given density from the equation:


density=massvolume

This means that: Mass = density x volume


Step 3: Determine atoms Ag. The flow of the solution will be like this: 

mass Ag  (molar mass Ag)  → moles Ag (Avogadro’s number)  → atoms Ag  

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Problem Details

You are given a cube of silver metal that measures 1.050 cm on each edge. The density of silver is 10.5 g/cm3.

How many atoms are in this cube?