We are given the following mixture of reactions:
2 KClO3 (s) → 2 KCl(s) + 3 O2(g)
2 KHCO3 (s) → K2O(s) + H2O(g) + 2 CO2(g)
K2CO3(s) → K2O(s) + CO2(g)
A mixture containing KClO3, K2CO3, KHCO3, and KCl was heated, producing CO2,O2, and H2O gases according to the following equations:
2 2KClO3 (s) → 2KCl(s) + 3 O2 (g)
2 KHCO3 (s) → K2O(s) + H2O(g) + 2CO2 (g)
K2CO3(s) → K2O(s) + CO2 (g)
The KCl does not react under the conditions of the reaction. 100.0 g of the mixture produces 1.80 g of H2O, 13.18 g of CO2, and 4.10 g of O2. (Assume complete decomposition of the mixture.)
You may want to reference (Pages 106 - 110) Section 3.7 while completing this problem.
How many grams of KClO3 were in the original mixture?
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