**Step 1: **The reaction would be:

**C**_{x}**H _{y}O_{z} + O_{2} → CO_{2} + H_{2}O**

The mass of C and H:

$\mathbf{Mass}\mathbf{}\mathbf{C}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{43}\mathbf{}\overline{)\mathbf{g}\mathbf{}{\mathbf{CO}}_{\mathbf{2}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{mol}\mathbf{}{\mathbf{CO}}_{\mathbf{2}}}}{\mathbf{44}\mathbf{.}\mathbf{01}\mathbf{}\overline{)\mathbf{g}\mathbf{}{\mathbf{CO}}_{\mathbf{2}}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{mol}\mathbf{}\mathbf{C}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mol}\mathbf{}{\mathbf{CO}}_{\mathbf{2}}}}\mathbf{\times}\frac{\mathbf{12}\mathbf{.}\mathbf{01}\mathbf{}\mathbf{g}\mathbf{}\mathbf{C}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mol}\mathbf{}\mathbf{C}}}$

Vanillin, the dominant flavoring in vanilla, contains C, H, and O. When 1.05 g of this substance is completely combusted, 2.43 g of CO_{2} and 0.50 g of H_{2}O are produced.

What is the empirical formula of vanillin?

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