# Problem: Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca ( OH )2.You may want to reference (Pages 187 - 190) Section 5.7 while completing this problem.From the following enthalpy of reaction data and data in Appendix C, calculate ΔH°f for CaC2 is:CaC2(s) + 2H2O(l) → Ca(OH)2(s) + C2H2(g) ΔH° = -127.2 kJ

###### FREE Expert Solution

Reaction: CaC2(s) + 2H2O(l) → Ca(OH)2(s) + C2H2(g) ΔH° = -127.2 kJ

$\overline{){\mathbf{∆}}{{\mathbf{H}}}_{{\mathbf{rxn}}}{\mathbf{=}}{\mathbf{∆}}{{\mathbf{H}}}_{\mathbf{f}\mathbf{,}\mathbf{products}}{\mathbf{-}}{\mathbf{∆}}{{\mathbf{H}}}_{\mathbf{f}\mathbf{,}\mathbf{reactants}}}$

${\mathbf{∆}}{{\mathbf{H}}}_{{\mathbf{rxn}}}{\mathbf{=}}\left[\left(∆{H}_{f,\mathrm{Ca}{\left(\mathrm{OH}\right)}_{2}}\right)+\left(∆{H}_{f,{C}_{2}{H}_{2}}\right)\right]{\mathbf{-}}{\mathbf{\left[}}\left(∆{H}_{f,\mathrm{Ca}{C}_{2}}\right){\mathbf{+}}\mathbf{\left(}\mathbf{2}\mathbf{×}\mathbf{∆}{\mathbf{H}}_{\mathbf{f}\mathbf{,}{\mathbf{H}}_{\mathbf{2}}\mathbf{O}}\mathbf{\right)}{\mathbf{\right]}}$

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###### Problem Details

Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca ( OH )2.

You may want to reference (Pages 187 - 190) Section 5.7 while completing this problem.

From the following enthalpy of reaction data and data in Appendix C, calculate ΔH°f for CaCis:

CaC2(s) + 2H2O(l) → Ca(OH)2(s) + C2H2(g) ΔH° = -127.2 kJ