Problem: Enthalpy diagram for combustion of 1 mol of methane. The enthalpy change of the one-step reaction equals the sum of the enthalpy changes of the reaction run in two steps: -890 kJ = -802 kJ + (-88 kJ).What process corresponds to the -88 kJ enthalpy change?

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The overall reaction is: CH4 (gas) plus 2 O2 (gas) goes to CO2 (gas) plus 2 H2O (liquid).  The enthalpy change from the reactants to the products is negative 890 kilojoules. The diagram also shows the enthalpy changes in two steps.  The enthalpy change from the reactants to CO2 (gas) plus 2 H2O (gas) is negative 802 kilojoules, and the enthalpy change from these to the products is negative 88 kilojoules.
Enthalpy diagram for combustion of 1 mol of methane. The enthalpy change of the one-step reaction equals the sum of the enthalpy changes of the reaction run in two steps: -890 kJ = -802 kJ + (-88 kJ).

What process corresponds to the -88 kJ enthalpy change?

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