Problem: Calculate the enthalpy change for the reaction: P4O6(s) + 2 O2(g) → P4O10(s), given the following enthalpies of reaction:P4(s) + 3 O2(g) → P4O6(s), ΔH = –1640.1 kJP4(s) + 5O2(g) → P4O10(s), ΔH = –2940.1 kJ

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(1) P4(s) + 3 O2(g) → P4O6(s)               ΔH = –1640.1 kJ

(2) P4(s) + 5O2(g) → P4O10(s)             ΔH = –2940.1 kJ

We shall modify the given reactions to arrive at the overall reaction. Any modification to the reaction is reflected in the value of ΔH for the reaction.

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Problem Details

Calculate the enthalpy change for the reaction: P4O6(s) + 2 O2(g) → P4O10(s), given the following enthalpies of reaction:
P4(s) + 3 O2(g) → P4O6(s), ΔH = –1640.1 kJ
P4(s) + 5O2(g) → P4O10(s), ΔH = –2940.1 kJ

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Based on our data, we think this problem is relevant for Professor Poniatowski's class at UMICH.