# Problem: How many kJ of heat are needed to raise the temperature of 13.00 kg of liquid water from 24.5 oC to 46.5 oC?

###### FREE Expert Solution

We’re being asked to determine the kJ of heat needed to raise the temperature of 13.00 kg of liquid water from 24.5 °C to 46.5 °C

We can solve for the heat,q  needed using the equation:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{mc}}{\mathbf{∆}}{\mathbf{T}}}$

where m = mass (in grams), c = specific heat, ΔT = change in temperature = final T – initial T

We’re given the following values:

m = 13.00 kg  (Convert kg to g: 1 kg = 103 g)

c = 4.184 J/g•°C (refer to textbooks/online)

ΔT = 46.5°C - 24.5°C = 22 °C

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###### Problem Details

How many kJ of heat are needed to raise the temperature of 13.00 kg of liquid water from 24.5 oC to 46.5 oC?