We’re being asked to determine the kJ of heat needed to raise the temperature of 13.00 kg of liquid water from 24.5 °C to 46.5 °C.
We can solve for the heat,q needed using the equation:
where m = mass (in grams), c = specific heat, ΔT = change in temperature = final T – initial T.
We’re given the following values:
m = 13.00 kg (Convert kg to g: 1 kg = 103 g)
c = 4.184 J/g•°C (refer to textbooks/online)
ΔT = 46.5°C - 24.5°C = 22 °C
How many kJ of heat are needed to raise the temperature of 13.00 kg of liquid water from 24.5 oC to 46.5 oC?
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