Practice: The solubility of KClO3 in water at 30ºC is 10 g per 100 mL of water. A 0.95 M solution of KClO3 in water at 30ºC is:
Subjects
Sections | |||
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Solutions: Solubility and Intermolecular Forces | 18 mins | 0 completed | Learn |
Molality | 15 mins | 0 completed | Learn |
Parts per Million (ppm) | 13 mins | 0 completed | Learn Summary |
Mole Fraction | 7 mins | 0 completed | Learn |
Solutions: Mass Percent | 11 mins | 0 completed | Learn |
Types of Aqueous Solutions | 9 mins | 0 completed | Learn |
Intro to Henry's Law | 4 mins | 0 completed | Learn |
Henry's Law Calculations | 13 mins | 0 completed | Learn |
The Colligative Properties | 15 mins | 0 completed | Learn |
Boiling Point Elevation | 16 mins | 0 completed | Learn Summary |
Freezing Point Depression | 11 mins | 0 completed | Learn Summary |
Osmosis | 16 mins | 0 completed | Learn |
Osmotic Pressure | 6 mins | 0 completed | Learn |
Vapor Pressure Lowering (Raoult's Law) | 17 mins | 0 completed | Learn |
Additional Guides |
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The Freezing Point Depression (IGNORE) |
When an ionic solid dissolves, ions leave the solid and become dispersed in the solvent. Three possible aqueous solutions can be formed: saturated, unsaturated and supersaturated.
Concept #1: Solution Equilibrium
Concept #2: Types of Aqueous Solutions
Example #1: The solubility of a substance is 56 g per 100 mL of water at 20° C. A solution of this substance is prepared by dissolving 80 g in 100 mL of water at 75° C. The solution is then cooled slowly to 20° C without any solid forming. The solution is:
Practice: The solubility of KClO3 in water at 30ºC is 10 g per 100 mL of water. A 0.95 M solution of KClO3 in water at 30ºC is:
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