**Wavelength **is the distance from one crest of a wave to another, whereas **frequency** is the number of waves within a second.

The electromagnetic spectrum consists of varying forms of energy within oscillating electric and magnetic fields.

**Concept:** The Electromagnetic Spectrum

Welcome back guys. In this new video, we're going to take a look at the nature of light. Now, what we should realize is the visible light that we see with our eyes, it only represents a small section of all the possible lights that exists. The visible light that we see has a certain energy tied with it.

Now, there are light sources that are above that energy and below that energy. Taking into account all of these different types of energies, we have this image right here. This is known as our electromagnetic spectrum. You should see that we have here, these are gamma rays, we have X-rays, UV, here this is infrared, IR.

Now, between UV which is ultraviolet light and IR, which is infrared light, that's what we find our visible light spectrum. We're going to say our visible light spectrum—the range is really 390 nm to about 780 nm. We learned this in the school, roygbiv, so roygbiv. Remember, what is that stand for? We're going to say red, orange, yellow, green, blue, indigo and violet.

We're going to say here, it looks like violet, violet is around 400 nm, whereas red is around 780 nm. Remember, the visible light spectrum only represent a small section of the entire spectrum of colors. Now, after IR, there are these microwave, then we have radio waves, which we get in our car radios or at home, on our stereos. We have FM and then we have radio in between AM and then we have long radio waves.

These represent basically all the different types of light sources or light energies that exist. There is also a cosmic rays which are usually above gamma, the professors usually ignore those.

**Concept:** Wavelength & Frequency

We're going to say according to this graph, there are basically wave properties associated with this electromagnetic spectrum.

We're going to say there are two independent variables associated with this electromagnetic spectrum. We're going to say the first one uses the variable V which really stands for mu, the Greek mu. In it is the number of waves you have per second, that right there would be our frequency. It is expressed in units of seconds inverse or hertz. Just remember, seconds inverse or hertz mean the same exact thing.

The second variable associated with our electromagnetic spectrum is lambda. This represents the distance from one quest of a wave to the other and this is our wavelength. The units for wavelength are meters. We're going to say that in our electromagnetic spectrum, we have frequency and we have wavelength.

**Concept:** The relationship between Wavelength & Frequency

As you can see, we're going to say, it looks like long radio waves, they have the highest wavelength, because they're above 108 meters, but as a result their frequency is very low, so they would have the lowest frequency. On the other side, it looks like gamma rays is 10/24 for frequency, so these guys would have the highest frequency and on the bottom, therefore it'd have the lowest wavelength.

Looking out what happens to our frequency when our wavelength is affected. Remember, we've talked about this before, we would say that the relationship between frequency and wavelength is that they are inversely proportional, which means they're opposite of one another. The way you should understand it visually is like this, so we have light travels sometimes as waves according to some theories. Here are some waves. These represent a bunch of light particles together.

Now, what we're going to say here is that frequency is how many waves do you get per second? Then, here we're going to say that wavelength is the distance from one top of the wave to the other. In this image here, we'd say that, the distance is pretty big, so we'd say that the wavelength is high, but we only get three waves in a second. That's not that many. We'd say that our frequency is low.

Now, if we draw a different picture, this is roughly the same distance as the first set of waves that I've showed you, but here now, you would say that the distance from one top of the wave to the other decrease. The wavelength looks like it's very small, so the wavelength would be low. We also say that we get a lot more waves per second, for that period of time, so we'd say that frequency here is high.

Visually, this is how you would show that frequency and wavelength are inversely proportional. Meaning that they are opposite of one another. We've talked about this when we talked about the relationship between certain factors such as pressure and volume. They're inversely proportional to each other. Same way, wavelength and frequency are inversely proportional.

Now, what this have to do with our electromagnetic spectrum? Our electromagnetic spectrum is a way of associating light with energy. We're going to say here, highest frequency, frequency has a direct relationship to energy. We'd say that gamma rays according to this spectrum have the highest frequency and therefore they have the highest energy. So they're both directly related to each other.

Remember, wavelength and frequency are opposites of one another. If my energy is high, therefore my wavelength would be low. On this other side, because my frequency is low, that means my energy is low.

It's going to become important that you guys remember the order of these different types of light sources, because your professor will easily ask one of them on the exam, 'Rank these in terms of increasing energy. Rank these in terms of increasing frequency.' It becomes important to remember the order.

**Wavelength** and **Frequency** are inversely proportionally, meaning that if one increases then the other one must be decrease.

**Problem:** A. Based on the images of different electromagnetic waves, answer each of the following questions.

**Concept:** Converting between Wavelength & Frequency

In this new video, we're going to continue our discussions of the relationship between frequency and wavelength and see how do we mathematically go from one to the other. We're going to say that the speed of a wave or speed of a light wave is the product of the frequency times the wavelength or between mu

times lambda. We're going to say in a vacuum, all forms of radiation travel at a constant 3.00 times 10 to the 8 meters per second. This is a physical constant that's known as the speed of light. We're going to say the speed of light just equals our wavelength times our frequency.

Basically, we're going to look at this equation right here. With this his equation, we’re able to go from frequency to wavelength because C is always that number, 3.00 times 10 to the 8 meters per second.

To convert between wavelength & frequency we use the equation **c = ν λ**, where c equals the speed of light.

**Example:** Even the music we listen to deals with how energy travels to get to our car radio. If Power 96 broadcasts its music at 96.5 MHz (megahertz, or 10^{6} Hertz) find the wavelength in μm and Å of the radio waves.

**Problem:** PRACTICE: Calculate the frequency of the red light emitted by a neon sign with a wavelength of 663.8 nm.

Hospital X-ray generators emit X rays with wavelength of about 15.0 nm, where 1 nm = 10 ^{-}^{9} m. What is the energy of a photon in an X ray? Express answer in joules.

Watch Solution

Green light has a frequency of about 6.00 x 10 ^{14} s^{-1} . What is the energy of a photon of green light?

(4 sig. fig)

E = J

Watch Solution

Where h = 6.626 x 10 ^{-34} J s ( Planck's constant ) and c = 2.99 x 10^{ 8} m/s. What is the wavelength of a photon that has an energy of E = 4.13 x 10^{-19} J? (in meters). The equation for photon energy E is?

Watch Solution

The energy of a photon of light is given by E = hv. The frequency, v, of light and the wavelength, λ, are related through: v = c/λ where c is the speed of light, 2.998 x 10^{8} m/s. Arrange the following wavelengths of light from lowest energy to highest energy: 461 nm, 637 nm, 517 nm. What is the energetic of a photon light with a wavelength of 415 nm?

Watch Solution

What is the wavelength of light if the energy of a photon is 3.65 x 10 ^{-19} J?

**A) **545 nm

**B) **5.45 x 10^{-7} nm

**C) **1.84 x 10^{6} nm

**D) **5.51 x 10^{14} nm

**E) **654 nm

Watch Solution

A laser pulse produces 1.046 kJ of energy. It was experimentally determined that the pulse contains 3.50 x 10^{22} photons. Determine the wavelength of light (in meters) emitted by one photon.

**A) **6.65 x 10^{-3} m

**B) **1.50 x 10^{5} m

**C) **5.43 x 10^{-48} m

**D) **1.50 x 10^{2} m

**E) **6.65 x 10^{-6} m

Watch Solution

Consider a hydrogen atom in the ground state. What is the energy (in J) of its electron?

Now consider an excited-state hydrogen atom. What is the energy (in J) of the electron in the n = 3 level?

Watch Solution

What is the wavelength (m) of light that has a frequency of 1.20 x 10 ^{13} s^{-1}

a) 2.50 x 10^{-5}

b) 25.0

c) 0.0400

d) 4.00 x 10^{4}

e) 2.5

Watch Solution

Two electromagnetic waves are represented below.

Wave (b) has the

a) higher frequency and higher energy than Wave (a).

b) lower frequency and lower energy than wave (a)

c) higher frequency and lower energy than wave (a).

d) lower frequency and higher energy than wave (a).

e) more information is needed.

Watch Solution

What is the energy (J) of a photon of a 1 km radio wave?

a) 1 x 10^{-25}

b) 1 x 10^{-28}

c) 2 x 10^{-25}

d) 2 x 10^{-28}

e) 5 x 10^{-25}

Watch Solution

It takes 238 kJ/mol to break a carbon-iodine bond. Calculate the frequency of light for which one carbon-iodine bond could be broken by absorbing a single photon.

a) 5.03 x 10^{-7}s^{-1}

b) 5.96 x 10^{11 }s^{-1}

c) 3.59 x 10^{35} s^{-1}

d) 3.59 x 10^{38 }s^{-1}

e) 5.96 x 10^{14 }s^{-1}

Watch Solution

Of the following, ______________ radiation has the longest wavelength and _____________ radiation has the greatest energy.

infrared gamma visible

a) infrared, gamma

b) gamma, infrared

c) visible, gamma

d) infrared, visible

e) visible, infrared

Watch Solution

Which one of the following types of radiation has the shortest wavelength, the greatest energy AND the highest frequency?

A. ultraviolet radiation

B. infrared radiation

C. visible red light

D. visible blue light

E. none because short wavelength is associated with low energy and low frequency, not high energy and high frequency

Watch Solution

What is the energy (in kJ/mol) of red photons with a frequency equal to 4.00 x 10 ^{14} Hz?

A. 5.30 x 10^{2 }

B. 1.60 x 10^{2}

C. 480 x 10^{2 }

D. 480 x 10^{3}

E. 5.30 x 10^{3}

Watch Solution

Calculate the frequency of visible light having a wavelength of 686 nm.

A) 4.37 x 10^{14} /s

B) 4.37 x 10^{5} /s

C) 2.06 x 10^{2} /s

D) 2.29 x 10^{-15} /s

E) 2.29 x 10^{-6 }/s

Watch Solution

An ultraviolet (UV) light photon has a wavelength of 124.1 nm. What is its energy in joules?

Watch Solution

One type of ultraviolet light has a wavelength of 223 nm. Calculate the energy of one photon of this light.

a. 8.91 x 10 ^{-19} J

b. 6.95 x 10 ^{-19} J

c. 7.12 x 10 ^{-19} J

d. 7. 87 x 10 ^{-19} J

Watch Solution

What is the wavelength of a beam of light having a frequency of 6 × 10 ^{17} Hz?

1. 1.8 × 10 ^{21} nm

2. 2 nm

3. 0.5 nm

4. 50 nm

Watch Solution

My microwave operates at a wavelength of 300.0 mm (note units). What is the energy of a mole of photons generated by this microwave? The value of Planck’s constant, h = 6.63 x 10^{-34} J s.

a. 4.3 kJ

b. 4.3 x 10^{-5} kJ

c. 330 kJ

d. 4.0 x 10^{-4} kJ

e. 5.5 x 10^{-25} kJ

Watch Solution

A line in the spectrum of an element was observed to have a frequesncy of 5.17 x 10^{14} s ^{-1} . What is the wavelength of this radiation?

a. 5.80 x 10^{-7} meters

b. 1.72 x 10^{6} meters

c. 1.55 x 10^{23} meters

d. 1.77 x 10^{-4} meters

e. 174 meters

Watch Solution

Most of the light emitted by excited mercury atoms has wavelengths of 185, 254, 365, 436, 546 and 615 nm. Which one of the following frequencies is emitted by mercury atoms?

A) 1.4 x 10^{14} s^{-1}

B) 4.1 x 10^{14} s^{-1}

C) 8.2 x 10^{14} s^{-1}

D) 8.2 x 10^{15} s^{-1}

E) 4.1 x 10^{15} s^{-1}

Watch Solution

The first ionization energy of carbon is 1.81 aJ. Assuming an ionization efficiency of 22.35%, how many photons of the lowest possible frequency are required to ionize a sample of carbon that contains 5.32 x 10^{18} atoms?

a) 2.38 x 10^{19} photons

b) 4.20 x 10^{-20} photons

c) 2.73 x 10^{15} photons

d) 9.11 x 10^{6} photons

Watch Solution

What is the frequency of the medical X-ray at 0.052 nm?

Watch Solution

Slightly more than of the total energy from the Sun is infrared, which has a critical effect on the earth's climate. The wavelength of this infrared light is about 4.00 x 10^{-6} m.

What is the frequency of the infrared light described above?

A) 7.5 x 10^{13} Hz

B) 6.0 x 10^{13} Hz

C) 1.7 x 10^{-14 }Hz

D) 2.0 x 10^{5} Hz

What is the energy of the infrared light described above?

A) 9.9 x 10^{-31 }J

B) 5.0 x 10^{-20} J

C) 1.1 x 10^{-47 }J

D) 1.3 x 10^{-28} J

Watch Solution

It takes light with a wavelength of 212 nm to break the NH bond in ammonia. What energy is required and what is the NH bond strength?

1. 6.6×10^{−22} kJ/photon, 4 × 10^{−4} kJ/mol

2. 9.4 × 10^{−19} kJ/photon, 565 kJ/mol

3. 9.4 × 10^{−22 }kJ/photon, 565 kJ/mol

4. 6.6 × 10^{−22 }kJ/photon, 0.40 kJ/mol

5. 9.4 × 10^{−22} kJ/photon, 565,000 kJ/mol

Watch Solution

The wavelength of light with a frequency of 3.30 × 10 ^{14} s ^{−1} is

1. 450 nm.

2. 909 nm.

3. 200 nm.

4. 650 nm.

Watch Solution

A low-pressure mercury-vapor lamp has a characteristic emission line at 253 nm. Knowing that this lamp is putting out 11.8 watts of light energy, how many mercury atoms are emitted per second during operation?

1. 5.25 x 10^{20} atoms

2. 7.11 x 10^{24} atoms

3. 1.50 x 10^{19} atoms

4. 1.08 x 1017 atoms

5. 7.86 x 10^{−19} atoms

6. 4.73 x 10^{5} atoms

Watch Solution

The speed of light in air

1. is independent of the wavelength and frequency of light.

2. depends on both the wavelength and the frequency of light.

3. depends only on the wavelength of light.

4. depends only on the frequency of the light.

Watch Solution

The energy of a photon is

1. nλ.

2. cλ.

3. c/λ .

4. λ/hc .

5. hc/λ .

Watch Solution

Carbon emits photons at 745 nm when exposed to blackbody radiation. How much energy would be obtained if 44g of carbon were irradiated? Assume each carbon atom emits one photon.

a. 9.1 x 10 ^{5} J

b. 2.7 x 10 ^{-19} J

c. 7.1 x 10 ^{6} J

d. 5.9 x 10^{ 5} J

Watch Solution

What is the energy in joules of a mole of photons with the energy of the 434 nm spectral line of hydrogen?

A) 5.78 × 10^{-25} J

B) 2.76 × 10^{-4} J

C) 434 J

D) 9.21 × 10^{-4} J

E) 2.76 × 10^{5} J

Watch Solution

How many photons of light with frequency 5.50 × 10 ^{15} Hz are required to provide 1 kJ of energy?

A) 2.74 × 10^{20} photons

B) 3.64 × 10^{-16} photons

C) 3.64 × 10^{-18} photons

D) 4.56 × 10^{-4} photons

E) 1.65 × 10^{44} photons

Watch Solution

Calculate the energy in kJ/mol of light with a wavelength of 360 nm.

A) 332 kJ/mol

B) 5.52 × 10^{-19} kJ/mol

C) 0.332 kJ/mol

D) 5.52 × 10^{-22} kJ/mol

E) 6.63 × 10^{3} kJ/mol

Watch Solution

Use Planck's equation to determine the energy, in J/photon, of radiation of frequency 5.8 × 10^{15} s^{-1}.

A) 5.8 ×10^{-25} J

B) 1.7 ×10^{-16} J

C) 3.8 ×10^{-18} J

D) 5.2 ×10^{-8} J

E) 1.7 ×10^{24} J

Watch Solution

Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The frequency of this light is __________ s^{-1}.

A) 1.58 ×10^{11}

B) 5.71 ×10^{5}

C) 1.75 ×10^{-15}

D) 5.71 ×10^{14}

E) 1.58 ×10^{2}

Watch Solution

The absorption of light of frequency 1.16 × 10 ^{11} Hz is required for CO molecules to go from the lowest rotational energy level to the next highest rotational energy level. Determine the energy for this transition in kJ/mol. h = 6.626 × 10^{-34} J ∙ s

A) 7.69 ×10^{-23} kJ/mol

B) 46.3 kJ/mol

C) 949 kJ/mol

D) 0.0463 kJ/mol

Watch Solution

Determine the longest wavelength of light required to remove an electron from a sample of potassium metal, if the binding energy for an electron in K is 1.76 × 10^{3} kJ/mol.

A) 113 nm

B) 885 nm

C) 68.0 nm

D) 147 nm

E) 387 nm

Watch Solution

How much energy (in kJ) do 3.0 moles of photons, all with a wavelength of 655 nm, contain?

A) 303 kJ

B) 394 kJ

C) 254 kJ

D) 548 kJ

E) 183 kJ

Watch Solution

How many photons are contained in a burst of yellow light (589 nm) from a sodium lamp that contains 609 kJ of energy?

A) 3.06 × 10^{30} photons

B) 2.48 × 10^{25} photons

C) 1.81 × 10^{24} photons

D) 3.37 × 10^{19} photons

E) 4.03 × 10^{28} photons

Watch Solution

Calculate the energy of the orange light emitted by a neon sign with a frequency of 4.89 × 10^{14} Hz.

A) 5.11 × 10^{-19} J

B) 3.09 × 10^{-19} J

C) 6.14 × 10^{-19} J

D) 1.63 × 10^{-19} J

E) 3.24 × 10^{-19} J

Watch Solution

Calculate the frequency of the green light emitted by a hydrogen atom with a wavelength of 486.1 nm.

A) 6.17 ×10^{14} s^{-1}

B) 1.46 ×10^{14} s^{-1}

C) 4.33 ×10^{14} s^{-1}

D) 1.62 ×10^{14} s^{-1}

E) 6.86 ×10^{14} s^{-1}

Watch Solution

Calculate the frequency of the red light emitted by a neon sign with a wavelength of 659.9 nm.

A) 4.55 ×10^{14} s^{-1}

B) 1.98 ×10^{14} s^{-1}

C) 3.32 ×10^{14} s^{-1}

D) 5.05 ×10^{14} s^{-1}

E) 2.20 ×10^{14} s^{-1}

Watch Solution

Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.88 ×10^{14} Hz.

A) 229 nm

B) 206 nm

C) 436 nm

D) 675 nm

E) 485 nm

Watch Solution

Calculate the wavelength (in nm) of the red light emitted by a neon sign with a frequency of 4.74 ×10^{14} Hz.

A) 704 nm

B) 158 nm

C) 466 nm

D) 142 nm

E) 633 nm

Watch Solution

Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this light is __________ J.

A) 3.79 ×10^{-28}

B) 2.64 ×10^{18}

C) 1.04 × 10^{-22}

D) 1.04 × 10^{-31}

E) 3.79 ×10^{-19}

Watch Solution

A mixture of argon and mercury vapor used in advertising signs emits light of wavelength 560 nm.

Calculate the energy change resulting from the emission of 1.00 mol of photons at this wavelength.

1. 272.058

2. 184.162

3. 187.04

4. 213.759

5. 249.386

6. 217.646

7. 299.263

8. 199.509

9. 221,677

10. 225.859

Watch Solution

In 1.0 s, a 60 W bulb emits 11 J of energy in the form of infrared radiation (heat) of wavelength 1850 nm. How many photons of infrared radiation does the lamp generate in 1.0 s?

1. 6.82 x 10 ^{–14} photons

2. 1.04 x 10 ^{29} photons

3. 6.63 x 10 ^{23} photons

4. 1.10 x 10 ^{–19} photons

5. 1.02 x 10 ^{20} photons

Watch Solution

Many small appliances and electronics operate in the microwave region. If your television operates at a 21.25 GHz, then what is the wavelength in nm?

Watch Solution

What is the energy, in joules, of a mole of photons associated with visible light of wavelength 486 nm?

A) 2.46 × 10^{–4} J

B) 6.46 × 10^{–25} J

C) 246 kJ

D) 6.46 × 10^{–16} J

E) 12.4 kJ

Watch Solution

A photovoltaic cell converts light into electrical energy. Suppose a certain photovoltaic cell is only 63.5% efficient, in other words, that 63.5% of the light energy is ultimately recovered. If the energy output of this cell is used to heat water, how many 520 nm photons must be absorbed by the photovoltaic cell in order to heat 10.0 g of water from 20.0°C to 30.0°?

Watch Solution

Arrange the following spectral regions in order of increasing wavelength:

infrared, microwave, ultraviolet, visible.

A) ultraviolet < visible < infrared < microwave

B) microwave < visible < infrared < ultraviolet

C) ultraviolet < infrared < visible < microwave

D) microwave < infrared < visible < ultraviolet

Watch Solution

How much energy is contained in 2.5 moles of 455 nm photons?

Watch Solution

Which of the responses contains all the true statements and no others regarding electromagnetic radiation (light)?

I. As energy increases frequency decreases.

II. As wavelength increases energy decreases.

III. As wavelength increases frequency decreases.

IV. The product of wavelength and frequency is constant.

a) I, III and IV

b) I and II

c) I, II and IV

d) II, III and IV

e) III and IV

Watch Solution

If the frequency of an X-ray is 5.4 x 10 ^{18} Hz, what is the energy of one photon of this radiation?

a) 3.6 x 10^{-15} J

b) 1.6 x 10^{-27} J

c) 1.2 x 10^{-52} J

d) 2.7 x 10^{-10} J

e) 7.4 x 10^{-29} J

Watch Solution

What is the frequency of ultraviolet radiation having a wavelength or 46.3 nanometers?

a) 1.54 x 10^{-14} s^{-1}

b) 6.47 x 10^{15} s^{-1}

c) 1.54 x 10^{-16} s^{-1}

d) 6.47 x 10^{13} s^{-1}

e) 1.18 x 10^{-7} s^{-1}

Watch Solution

Which of the following statements is or are true?

1 An excited atom can return to a lower energy level by absorbing light energy.

2 An atom can be excited by emitting light energy.

3 As the energy of electromagnetic radiation increases, its frequency increases.

4 The frequency and wavelength of light are inversely proportional.

a) 1 and 2 only

b) 2 only

c) 2 and 3

d) 1 and 3

e) 3 and 4

Watch Solution

What is the energy of a photon of ultraviolet radiation, λ= 500 pm?

a) 1.11 x 10^{-49} J

b) 1.67 x 10^{-16} J

c) 9.95 x 10^{-33} J

d) 3.98 x 10^{-16} J

e) 7.24 x 10^{-12} J

Watch Solution

What is the wavelength of yellow light (in nanometers) having a frequency of 5.17 x 10^{14} s^{-1}?

a) 3.84 x 10^{-31} m

b) 5.80 x 10^{-7} m

c) 1.72 x 10^{-6} m

d) 5.80 x 10^{2} m

e) 1.72 x 10^{4} m

Watch Solution

A. Calculate the energy of a photon with a wavelength of 100 nm.

Convert the energy to units of kJ/mol.

Is this photon within the region for visible light, higher in energy, or lower in energy? ________________

B. How would you calculate the speed of hydrogen atom with a wavelength of 1.00 nm? Set up the equation, including conversion factors, but do not do the calculation.

Watch Solution

Medical applications of electromagnetic radiation cover the entire spectrum, from gamma rays used to diagnose and treat cancer, to radio waves used in magnetic resonance imaging (MRI). Until recently the tools did not exist to exploit the range from 0.1 to 10 THz, leading some to call this region of the spectrum from 0.1 to 10 THz the “terahertz gap.” But that gap is starting to close as new techniques are developed to explore the terahertz region of the spectrum (Chemistry & Engineering News, **2015**, 93, 10-14). It was discovered the terahertz light causes groups of water molecules to coalesce and disassemble repeatedly, and because water permeates most biological studies, terahertz spectroscopy holds considerable promise an important new tool in medical science.

A. Calculate the energy (in J) of a 2.4 THz photon.

(1 THz = 1 x 10^{12} Hz = 1 x 10^{12} s ^{-1} )

Convert your answer above from J to kJ/mol.

B. Calculate the wavelength (in nm) of a 2.4 THz photon.

Do you expect 2.4 THz light to be dangerous to biological tissue? Explain your reasoning.

Watch Solution

Ham radio operators often broadcast on the 6-meter band. The frequency of this electromagnetic radiation is __________ MHz.

a) 50

b) 20

c) 2.0

d) 200

e) 500

Watch Solution

What wavelength of light will be required to remove an electron from the n = 3 shell of a hydrogen atom?

Watch Solution

How much total energy (in MJ/mol) would it take to remove the electrons from a mole of hydrogen atoms?

The ionization energy for a hydrogen atom is 2.178 x 10^{-18} J.

(A) 3.617 x 10 ^{-42} MJ

(B) 1.312 MJ

(C) 2.765 MJ

(D) 1.312 x 10 ^{6} MJ

(E) 2.765 x 10 ^{35} MJ

Watch Solution

Assuming an ionization efficiency of 18.0%, how many photons are needed to ionize 1.00 x 10^{16} atoms?

Watch Solution

The carcinogen, CCl_{4 }has been dumped into a holding pond. CCl_{4} will begin to decompose by the following reaction:

CCl_{4} → Cl_{3}C• + Cl• D(C—Cl) = 327 kJ/mol

If sunlight striking the earth has a frequency range from approximately 6.7 x 10 ^{14 }Hz to 4.4 x 10^{14 } Hz. Can you expect sunlight alone to affect the decomposition?

Explain. h= 6.63 x 10 ^{-34} J•sec; c = 3.00 x 10^{8} m/sec

Watch Solution

R = 2.18x10^{-18} J; h = 6.626x10^{-34} J•sec or 6.626x10^{-34} kg•m^{2} sec^{-1};

c = 3.00 x 10 ^{8} m•sec^{-1}; 1eV= 1.602x10^{-19} J

a.) What is the energy of a photon with a wavelength of 335 nm?

b.) If a metal that has a work function of 2.80 eV, what wavelength of light is required to generate electrons with a kinetic energy of 1.02 eV?

c.) If a reaction is exothermic, does it mean that ΔE for the reaction is negative? Explain.

Watch Solution

A hydrogen atom emits light in an electronic transition going from n=4 to n=2 lower shell.

1.) What is the frequency of this light?

2.) What wavelength is this and what color will it appear to the eye?

(*R *= 2.18x10 ^{-18} J; h = 6.63 x 10 ^{-34} J•sec; c = 3.00x10 ^{8} m/sec;1 nm = 10 ^{-9} m)

Watch Solution

Blu-ray DVDs are read with a laser that has a wavelength of 405 nm. Calculate the energy of one mole of photons from this type of laser.

(a) 345 kJ

(b) 2.96×10 ^{5} J

(c) 3.38×10 ^{−6} J

(d) 4.91×10 ^{−19} J

(e) 4.73×10 ^{4} J

Watch Solution

You have measured the energy of a photon that you captured in a specialized detector, and found that the photon had an energy of 6.89 × 10 ^{−24} J. Based on the scale below, what type of photon was detected?

(a) Gamma(γ) ray

(b) X ray

(c) Ultraviolet (UV)/Visible

(d) Infrared (IR)

(e) Microwave

Watch Solution

Determine the shortest frequency of light required to remove an electron from a sample of a metal, if the binding (threshold) energy of the metal is 3.14x10^{3 }kJ/mol.

a. 7.87x10^{15 }Hz

b. 4.74x10^{15} Hz

c. 2.11x10^{15 }Hz

d. 1.27x10^{15} Hz

e. 6.19x10^{15} Hz

Watch Solution

Determine the longest wavelength of light required to remove an electron from an atom of a metal, if the binding energy for an electron in that metal is 309 kJ/mol.

a. 147 nm

b. 68.0 nm

c. 113 nm

d. 885 nm

e. 387nm

Watch Solution

How many photons of light with frequency 5.50 x 10 ^{15 }Hz are required to provide 1 kJ of energy?

A. 1.65 x 10 ^{44 }photons

B. 2.74 x 10 ^{20} photons

C. 3.64 x 10 ^{-16} photons

D. 3.64 x 10 ^{-18} photons

E. 4.56 x 10 ^{-4} photons

Watch Solution

What is the frequency of a 534 nm photon?

1. 6.04e^{+14}

2. 5.56e^{+14}

3. 6.98e^{+14}

4. 4.29e^{+14}

5. 5.21e^{+14}

6. 4.76e^{+14 }

7. 5.8e^{+14}

8. 4.17e^{+14}

9. 4.91e^{+14}

10. 5.62^{+14}

Watch Solution

Ultraviolet light emits a total of 2.5 × 10 ^{–17} J of light at a wavelength of 9.8 × 10 ^{–7} m. How many photons does this correspond to?

a) 1

b) 10

c) 25

d) 100

e) 125

Watch Solution

What is the frequency (Hz) of an infrared light that emits 24.5 kJ/mol of energy?

a) 3.70 × 10 ^{34}

b) 6.14 × 10 ^{13}

c) 4.92 × 10 ^{19 }

d) 8.17 × 10 ^{–8 }

e) 2.70 × 10 ^{–35}

Watch Solution

What is the wavelength of a particle that has an energy of 4.41 × 10 ^{–19 }J?

a) 441 nm

b) 450 nm

c) 227 nm

d) 222 nm

e) 199 nm

Watch Solution

Which of the following statements is NOT true?

a) Energy increases as the wavelength decreases.

b) Energy increases as the frequency increases.

c) Frequency increases as the wavelength decreases.

d) All of the statements are true.

Watch Solution

Determine the wavelength (in nm) of an X-ray with a frequency of 4.2 × 10 ^{18}Hz.

a. 7.1 × 10 ^{–11}

b. 7.1 × 10 ^{–2 }

c. 1.3 × 10 ^{27}

d. 1.4 × 10 ^{10 }

e. 7.1 × 10 ^{–18}

Watch Solution

For light with a wavelength of 12.5 nm, determine the energy of light in kJ/mol.

A. 4.99 * 10^{−18}

B. 0.00957

C. 4.99

D. 9.57

E. 9570

Watch Solution

The binding energy of an electron in iron is 7.49 × 10 ^{–19} J. What is the maximum wavelength of light that can be used to eject electrons from iron?

A) 265 nm

B) 636 nm

C) 542 nm

D) 339 nm

E) 800 nm

Watch Solution

As the wavelength of light increases, which is also true of light?

A. frequency decreases and energy decreases

B. frequency decreases and energy increases

C. frequency increases and energy decreases

D. frequency increases and energy decreases

E. frequency and energy remain constant

Watch Solution

Which wave form for a particle trapped in a 1-dimensional box has the highest energy?

Watch Solution

Which wave form for a particle trapped in a 1-dimensional box has the lowest energy?

Watch Solution