Hardy-Weinberg Model Video Lessons

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Problem: Human blood type is determined by three alleles IA, IB, and IO. The alleles IA and IB are co-dominant to each other, and both are dominant to IO. Within a large, randomly mating population (640,000 individuals), the frequencies for the blood type alleles are 0.3 for the IA allele, 0.6 for the IO allele, and 0.1 for the IB allele. Calculate the expected numbers of people in the population having blood type O.A. O = 243,400 peopleB. O = 324,000 peopleC. O = 194,400 peopleD. O = 230,400 people

FREE Expert Solution

For blood type groups in Hardy-Weinberg equilibrium, there would be three alleles, p, q, and r, and these would correspond to the alleles IA, IB, and IO, respectively. For these three alleles, p + q + r = 1. Furthermore, these values can be used to compute for the genotypic frequencies: p2 is for IAIA, 2pq is for the heterozygous IAIB, q2 is for IBIB2pr is for heterozygous IAIOwhile 2qr is for heterozygous IBIO, and lastly, r2 is for the homozygous recessive, IOIO.

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Problem Details

Human blood type is determined by three alleles IA, IB, and IO. The alleles IA and IB are co-dominant to each other, and both are dominant to IO. Within a large, randomly mating population (640,000 individuals), the frequencies for the blood type alleles are 0.3 for the IA allele, 0.6 for the IO allele, and 0.1 for the IB allele. Calculate the expected numbers of people in the population having blood type O.

A. O = 243,400 people

B. O = 324,000 people

C. O = 194,400 people

D. O = 230,400 people

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