Independent Assortment Video Lessons

Video Thumbnail

Concept

Problem: In probiscus monkeys, N=long nose, and n=short nose. Cross a homozygous dominant long-nosed monkey (NN) with a homozygous recessive short-nosed monkey (nn). Show the Punnet square, and provide the phenotypic and genotypic ratios.

FREE Expert Solution

In the given problem, the subject gene is N/n, which determines nose character. The parents for the cross is a homozygous dominant, NN, and a homozygous recessive, nn.

View Complete Written Solution
Problem Details

In probiscus monkeys, N=long nose, and n=short nose. Cross a homozygous dominant long-nosed monkey (NN) with a homozygous recessive short-nosed monkey (nn). Show the Punnet square, and provide the phenotypic and genotypic ratios.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Independent Assortment concept. You can view video lessons to learn Independent Assortment. Or if you need more Independent Assortment practice, you can also practice Independent Assortment practice problems.