The given ratios purine-pyrimidine ratio suggests that the given DNA sample is most likely double-stranded. However, non-equal amounts of A and T, as well as G and C (i.e. their ratios are not equal to 1), suggests otherwise. Thus, we simply proceed to systems of equations.
Note that the ratio of purines to pyrimidines is 1, so A + G = T + C
Chargaff's results yielded a molar ratio of 1.67 for A to G in yeast DNA, 1.92 for T to C, 1.03 for A to T, and 1.20 for G to C. The ratio of purines to pyrimidines is 1.00. Calculate the mole fractions of A, G, T, and C in yeast DNA.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Nucleic Acids concept. You can view video lessons to learn Nucleic Acids. Or if you need more Nucleic Acids practice, you can also practice Nucleic Acids practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Due-Goodwin's class at VANDERBILT.