Extensions to Mendel Video Lessons

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Problem: In swine, when a pure-breeding red is crossed to a pure-breeding white, the F1 are all red. However, the F2 shows 9/16 red, 1/16 white,and 6/16 are a new color, sandy. Thesandy phenotype is mots likely determined byA. complementary alleles of two different genes.B. a heterozygote of the alleles determines red and white.C. recessive epistasis.D. the presence of a dominant allele at either of two loci where red is determined by the dominant alleles of both loci.

FREE Expert Solution

For this problem, having 16 possible outcomes suggests the involvement of 2 genes for color. And as shown by the F1 progeny, being a cross between two different true-breeding individuals, red is the dominant color. Thus, we let the genotype of the true-breeding red to be RRSS while the genotype of the true-breeding white is rrss. Their F1 progeny will all be dihybrids, RrSs.

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Problem Details

In swine, when a pure-breeding red is crossed to a pure-breeding white, the F1 are all red. However, the F2 shows 9/16 red, 1/16 white,and 6/16 are a new color, sandy. Thesandy phenotype is mots likely determined by

A. complementary alleles of two different genes.

B. a heterozygote of the alleles determines red and white.

C. recessive epistasis.

D. the presence of a dominant allele at either of two loci where red is determined by the dominant alleles of both loci.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Extensions to Mendel concept. You can view video lessons to learn Extensions to Mendel. Or if you need more Extensions to Mendel practice, you can also practice Extensions to Mendel practice problems.

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Based on our data, we think this problem is relevant for Professor King's class at UCF.