Ch.17 - Gene ExpressionWorksheetSee all chapters
All Chapters
Ch.1 - Introduction to Biology
Ch.2 - Chemistry
Ch.3 - Water
Ch.4 - Carbon
Ch.5 - Biological Molecules
Ch.6 - Cells
Ch.7 - The Membrane
Ch.8 - Energy and Metabolism
Ch.9 - Respiration
Ch.10 - Photosynthesis
Ch.11 - Cell Signaling
Ch.12 - Cell Division
Ch.13 - Meiosis
Ch.14 - Mendelian Genetics
Ch.15 - Chromosomal Theory of Inheritance
Ch.16 - DNA Synthesis
Ch.17 - Gene Expression
Ch.18 - Regulation of Expression
Ch.19 - Viruses
Ch.20 - Biotechnology
Ch.21 - Genomics
Ch.22 - Development
Ch.23 - Evolution by Natural Selection
Ch.24 - Evolution of Populations
Ch.25 - Speciation
Ch.26 - History of Life on Earth
Ch.27 - Phylogeny
Ch.28 - Prokaryotes
Ch.29 - Protists
Ch.30 - Plants
Ch.31 - Fungi
Ch.32 - Overview of Animals
Ch.33 - Invertebrates
Ch.34 - Vertebrates
Ch.35 - Plant Anatomy
Ch.36 - Vascular Plant Transport
Ch.37 - Soil
Ch.38 - Plant Reproduction
Ch.39 - Plant Sensation and Response
Ch.40 - Animal Form and Function
Ch.41 - Digestive System
Ch.42 - Circulatory System
Ch.43 - Immune System
Ch.44 - Osmoregulation and Excretion
Ch.45 - Endocrine System
Ch.46 - Animal Reproduction
Ch.47 - Nervous System
Ch.48 - Sensory Systems
Ch.49 - Muscle Systems
Ch.50 - Ecology
Ch.51 - Animal Behavior
Ch.52 - Population Ecology
Ch.53 - Community Ecology
Ch.54 - Ecosystems
Ch.55 - Conservation Biology
Gene Expression and the Genetic Code
RNA Processing

Solution: A nontemplate strand of bacterial DNA has the following base sequence: 5' - ATGATACTAAGGCCC - 3'Determine the sequence of the amino acids that will be encoded. 


A nontemplate strand of bacterial DNA has the following base sequence: 


Determine the sequence of the amino acids that will be encoded. 


The strand that is used as template during the transcription process is called the template strand. It is usually set in the 3' to 5' direction since the RNA polymerase will synthesize the mRNA transcript in the 5' to 3' direction, which is antiparallel to the template. Following the principles of RNA polymerase, this mRNA transcript will be quite equivalent to the nontemplate strand as they are both complementary to the template strand. Their only difference is that the mRNA transcript has Us instead of Ts. resulting in an mRNA transcript of 5' - AUGAUACUAAGGCCC - 3'.

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