Practice: Calculate the pCN from the titration of 40.0 mL of 0.060 M NaCN with 20.0 mL of 0.050 M AgC2H3O2. The solubility product constant of AgCN is 2.2 x 10-16.
Concept #1:
A titration curve follows the change in either the analyte’s or titrant’s concentration as a function of the titrant’s volume.
Concept #2: Before the equivalence point has been reached there is an excess of the analyte.
Concept #3: At the equivalence point there is an equal amount of the analyte and the titrant.
Concept #4: After the equivalence point has been reached there is an excess of the titrant.
Example #1: Calculate the [F–] from the titration of 130.0 mL of 0.120 M KF with 150.0 mL of 0.100 M BaCl2. The solubility product constant of BaF2 is 1.5 x 10-6.
Practice: Calculate the pCN from the titration of 40.0 mL of 0.060 M NaCN with 20.0 mL of 0.050 M AgC2H3O2. The solubility product constant of AgCN is 2.2 x 10-16.
