# Problem: Calculate the pH of 200.00 mL of 0.20 M H3PO4 with addition of 125.0 mL of 0.35 M NaOH. Ka1 = 7.11 x 10-3, Ka2 = 6.34 x 10-8 and Ka2 = 4.22 x 10-13.

###### Problem Details

Calculate the pH of 200.00 mL of 0.20 M H3PO4 with addition of 125.0 mL of 0.35 M NaOH. Ka1 = 7.11 x 10-3, Ka2 = 6.34 x 10-8 and Ka2 = 4.22 x 10-13

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