For H2(g) + Br2(g) ⇌ 2 HBr(g), K = 7.2 × 10–4 at 1362 K and ΔHº is positive. A vessel is charged with 48.0 Pa HBr, 1370 Pa H2, and 3310 Pa Br2 at 1362 K. Will the reaction proceed to the left or the right to reach equilibrium?
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