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Ch.16 - Electroanalytical TechniquesWorksheetSee all chapters
All Chapters
Ch.1 - Chemical Measurements
Ch.2 - Tools of the Trade
Ch.3 - Experimental Error
Ch.4 + 5 - Statistics, Quality Assurance and Calibration Methods
Ch.6 - Chemical Equilibrium
Ch.7 - Activity and the Systematic Treatment of Equilibrium
Ch.8 - Monoprotic Acid-Base Equilibria
Ch.9 - Polyprotic Acid-Base Equilibria
Ch.10 - Acid-Base Titrations
Ch.11 - EDTA Titrations
Ch.12 - Advanced Topics in Equilibrium
Ch.13 - Fundamentals of Electrochemistry
Ch.14 - Electrodes and Potentiometry
Ch.15 - Redox Titrations
Ch.16 - Electroanalytical Techniques
Ch.17 - Fundamentals of Spectrophotometry
BONUS: Chemical Kinetics
Sections
Fundamentals of Electrolysis
Gravimetric Analysis
Coulometry
Voltammetry

In Gravimetric Analysis the mass of a product in a chemical reaction is used to calculate the amount of the original analyte.

Introduction to Gravimetric Analysis

Example #1:

A 25.00 mL solution containing Br was treated with excess PbSO4 to precipitate 0.7550 g of PbBr2. What was the molarity of the Br in the unknown? 

PbSO4 (s)   +   2 Br (aq) → PbBr2 (s)   +SO42– (aq)

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Example #2: The Fe in a 1.1530 g sample of iron ore is precipitated as Fe2O3 x H2O by the addition of NH3. The residue is ignited at high temperatures to give 0.6310 g of pure Fe2O3. Calculate the weight percent of Fe in the ore. 

2 Fe3+ (aq) +  6 OH (aq) → Fe2O3 * x H2O

Fe2OxH2O +  heat  → Fe2O3 +  6 x H2O

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Electrogravimetric Analysis Calculations

Example #3: The reaction between piperazine and acetic acid creates an adduct product known as piperazine diacetate. 

 A 7.50 g sample of impure piperazine contained 83.01% piperazine. How many grams of piperazine diacetate would be formed in the process?  


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Example #4: The amount of iron within an ore sample was determined by an oxidation-reduction titration using potassium permanganate, KMnO­4, as the titrant. A 0.5600 g sample of the ore was placed into acid and the newly freed Fe3+ was then reduced to Fe2+. The titration of this solution required 39.82 mL of 0.0315 M KMnO­4 to reach the end-point. Determine the mass percent of Fe2O3 in the sample. 

MnO4   +5 Fe2+   + 8 H+ → Mn2+  +  5 Fe3+  +  4 H2O

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